6x+1x=6x^2

Solution for 6x+1x=6x^2 equation:

6x+1x=6x^2

We move all terms to the left:

6x+1x-(6x^2)=0

determiningTheFunctionDomain
-6x^2+6x+1x=0

We add all the numbers together, and all the variables

-6x^2+7x=0

a = -6; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-6)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-6}=\frac{-14}{-12}
=1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-6}=\frac{0}{-12}
=0
$